Solution Manual Heat And Mass Transfer Cengel 5th Edition Chapter 3 New 〈480p · UHD〉

q = (20 - 0) / 0.5625 = 35.56 W/m²

where R is the thermal resistance, L is the thickness of the material, k is the thermal conductivity, and A is the area. q = (20 - 0) / 0

R = L / k * A

q = -k * A * (dT/dx)